What is the foci 4x^2+25y^2-50y-75=0 ?

The foci 4x^2+25y^2-50y-75=0 is (sqrt(21),1),(-sqrt(21),1)

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foci 4x^2+25y^2-50y-75=0

foci

4 x^{2} + 25 y^{2} - 50 y - 75 = 0

(21, 1), (- 21, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

4 x^{2} + 25 y^{2} - 50 y - 75 = 0 :

Ellipse with center

(h, k) = (0, 1), a = 5, b = 2

(0 + c, 1), (0 - c, 1)

Compute

c :

c = 5^{2} - 2^{2} : 21

(0 + 21, 1), (0 - 21, 1)

Refine

(21, 1), (- 21, 1)

\frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1

25 x^{2} + 4 y^{2} + 50 x - 16 y = 59

3 x^{2} + 7 y^{2} - 21 = 0

9 x^{2} + 6 y^{2} + 36 y = 0

\frac{( x - 1 ) ^{2}}{12} + \frac{y ^{2}}{8} = 100

What is the foci 4x^2+25y^2-50y-75=0 ?
The foci 4x^2+25y^2-50y-75=0 is (sqrt(21),1),(-sqrt(21),1)