What is the foci 9x^2+25y^2+90x=0 ?

The foci 9x^2+25y^2+90x=0 is (-1,0),(-9,0)

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foci 9x^2+25y^2+90x=0

foci

9 x^{2} + 25 y^{2} + 90 x = 0

(- 1, 0), (- 9, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

9 x^{2} + 25 y^{2} + 90 x = 0 :

Ellipse with center

(h, k) = (- 5, 0), a = 5, b = 3

(- 5 + c, 0), (- 5 - c, 0)

Compute

c :

c = 5^{2} - 3^{2} : 4

(- 5 + 4, 0), (- 5 - 4, 0)

Refine

(- 1, 0), (- 9, 0)

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27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

\frac{x ^{2}}{46} + \frac{( y + 8 ) ^{2}}{26} = 1

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0