What is the eccentricity (x^2)/(160)+(y^2)/(16)=1 ?

The eccentricity (x^2)/(160)+(y^2)/(16)=1 is 3/(sqrt(10))

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eccentricity (x^2)/(160)+(y^2)/(16)=1

eccentricity

\frac{x ^{2}}{160} + \frac{y ^{2}}{16} = 1

\frac{3}{10}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{160} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 410, b = 4

= \frac{( 4 10 ) ^{2} - 4 ^{2}}{4 10}

\frac{( 4 10 ) ^{2} - 4 ^{2}}{4 10} = \frac{3}{10}

= \frac{3}{10}

9 x^{2} + 25 y^{2} + 108 x - 200 y + 499 = 0

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

\frac{x ^{2}}{8} + \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

What is the eccentricity (x^2)/(160)+(y^2)/(16)=1 ?
The eccentricity (x^2)/(160)+(y^2)/(16)=1 is 3/(sqrt(10))