What is the vertices ((x+2)^2)/(20)-(y^2)/(20)=1 ?

The vertices ((x+2)^2)/(20)-(y^2)/(20)=1 is (-2+2sqrt(5),0),(-2-2sqrt(5),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices ((x+2)^2)/(20)-(y^2)/(20)=1

vertices

\frac{( x + 2 ) ^{2}}{20} - \frac{y ^{2}}{20} = 1

(- 2 + 25, 0), (- 2 - 25, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{( x + 2 ) ^{2}}{20} - \frac{y ^{2}}{20} = 1 :

Right-left Hyperbola with

(h, k) = (- 2, 0), a = 25, b = 25

(- 2 + 25, 0), (- 2 - 25, 0)

\frac{( y ) ^{2}}{121} - \frac{( x ) ^{2}}{81} = 1

\frac{( y - 2 ) ^{2}}{17} - \frac{( x - 8 ) ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1

\frac{x ^{2}}{4} - y^{2} = 1

What is the vertices ((x+2)^2)/(20)-(y^2)/(20)=1 ?
The vertices ((x+2)^2)/(20)-(y^2)/(20)=1 is (-2+2sqrt(5),0),(-2-2sqrt(5),0)