What is the foci (x^2}{81}-\frac{y^2)/9 =1 ?

The foci (x^2}{81}-\frac{y^2)/9 =1 is (3sqrt(10),0),(-3sqrt(10),0)

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foci (x^2}{81}-\frac{y^2)/9 =1

foci

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1

(310, 0), (- 310, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{81} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 9, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} + 3^{2} : 310

(0 + 310, 0), (0 - 310, 0)

Refine

(310, 0), (- 310, 0)

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

16 x^{2} - 25 y^{2} = 400

9 y^{2} - 16 x^{2} = 144

What is the foci (x^2}{81}-\frac{y^2)/9 =1 ?
The foci (x^2}{81}-\frac{y^2)/9 =1 is (3sqrt(10),0),(-3sqrt(10),0)