What is the foci (y^2)/(25)-(x^2)/(144)=1 ?

The foci (y^2)/(25)-(x^2)/(144)=1 is (0,13),(0,-13)

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foci (y^2)/(25)-(x^2)/(144)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 12

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 1 2^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

9 y^{2} - x^{2} + 2 x + 54 y + 62 = 0

16 x^{2} - 25 y^{2} = 400

9 y^{2} - 16 x^{2} = 144

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

What is the foci (y^2)/(25)-(x^2)/(144)=1 ?
The foci (y^2)/(25)-(x^2)/(144)=1 is (0,13),(0,-13)