Solution
Solution
Solution steps
Rewrite in the form of a standard hyperbola equation
Therefore Hyperbola properties are:
Popular Examples
foci (x^2}{25}+\frac{y^2)/4 =1foci vertices y=-(x^2)/(10)+(9x)/(10)+11/5vertices 2y^2-12y-x+5=0eccentricity 9x^2+9y^2+18x-18y+14=0eccentricity foci x^2=8yfoci
Frequently Asked Questions (FAQ)
What is (x^2)/4-y^2=1 ?
The solution to (x^2)/4-y^2=1 is Hyperbola with (h,k)=(0,0),a=2,b=1