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Popular >

foci x^2=8y

Solution

foci

x^{2} = 8 y

Solution

(0, 2)

Solution steps

Rewrite

x^{2} = 8 y

in the standard form:

4 \cdot 2 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + 2)

Refine

(0, 2)

Popular Examples

y^{2} + 4 x = 7

vertices (x^2}{16}-\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

foci 9x^2-16y^2=144 foci

9 x^{2} - 16 y^{2} = 144

asymptotes of (y^2}{16}-\frac{x^2)/9 =1 asymptotes

\frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

x = 2 y^{2}

Frequently Asked Questions (FAQ)

What is the foci x^2=8y ?
The foci x^2=8y is (0,2)