What is 2y^2-12y-x+5=0 ?

The solution to 2y^2-12y-x+5=0 is Parabola with (h,k)=(-13,3),p= 1/8

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2y^2-12y-x+5=0

2 y^{2} - 12 y - x + 5 = 0

(h, k) = (- 13, 3), p = \frac{1}{8}

Solution steps

2 y^{2} - 12 y - x + 5 = 0

Rewrite

2 y^{2} - 12 y - x + 5 = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- 13)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 13, 3), p = \frac{1}{8}

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

x^{2} = 8 y

y^{2} + 4 x = 7

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

9 x^{2} - 16 y^{2} = 144

What is 2y^2-12y-x+5=0 ?
The solution to 2y^2-12y-x+5=0 is Parabola with (h,k)=(-13,3),p= 1/8