What is the foci (y^2)/(16)-(x^2)/(36)=1 ?

The foci (y^2)/(16)-(x^2)/(36)=1 is (0,2sqrt(13)),(0,-2sqrt(13))

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foci (y^2)/(16)-(x^2)/(36)=1

foci

\frac{y ^{2}}{16} - \frac{x ^{2}}{36} = 1

(0, 213), (0, - 213)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{16} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 6^{2} : 213

(0, 0 + 213), (0, 0 - 213)

Refine

(0, 213), (0, - 213)

4 y^{2} - 9 x^{2} = 36

9 x^{2} - y^{2} = 36

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

16 x^{2} - 20 y^{2} - 320 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

What is the foci (y^2)/(16)-(x^2)/(36)=1 ?
The foci (y^2)/(16)-(x^2)/(36)=1 is (0,2sqrt(13)),(0,-2sqrt(13))