What is the foci 18x^2-32y^2=2 ?

The foci 18x^2-32y^2=2 is (5/12 ,0),(-5/12 ,0)

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foci 18x^2-32y^2=2

foci

18 x^{2} - 32 y^{2} = 2

(\frac{5}{12}, 0), (- \frac{5}{12}, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

18 x^{2} - 32 y^{2} = 2 :

Right-left Hyperbola with

(h, k) = (0, 0), a = \frac{1}{3}, b = \frac{1}{4}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (\frac{1}{3})^{2} + (\frac{1}{4})^{2} : \frac{5}{12}

(0 + \frac{5}{12}, 0), (0 - \frac{5}{12}, 0)

Refine

(\frac{5}{12}, 0), (- \frac{5}{12}, 0)

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

- 9 x^{2} + y^{2} + 54 x - 117 = 0

\frac{( y ^{2} )}{27} - \frac{( x ^{2} )}{9} = 1