What is the foci (y^2)/4-(x^2)/4 =1 ?

The foci (y^2)/4-(x^2)/4 =1 is (0,2sqrt(2)),(0,-2sqrt(2))

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foci (y^2)/4-(x^2)/4 =1

foci

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1

(0, 22), (0, - 22)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 2^{2} : 22

(0, 0 + 22), (0, 0 - 22)

Refine

(0, 22), (0, - 22)

\frac{( y + 2 ) ^{2}}{16} - \frac{( x - 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{100} - \frac{y ^{2}}{49} = 1

\frac{( y - ( - 2 ) ) ^{2}}{9} - \frac{( x - 5 ) ^{2}}{27} = 1

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( 3 x - 0 ) ^{2}}{90} = 1

- \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

What is the foci (y^2)/4-(x^2)/4 =1 ?
The foci (y^2)/4-(x^2)/4 =1 is (0,2sqrt(2)),(0,-2sqrt(2))