What is the center ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 ?

The center ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 is (2,3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1

center

\frac{( y - 3 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1

(2, 3)

Solution steps

\frac{( y - 3 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 3), a = 8, b = 8

And the center is:

(2, 3)

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

What is the center ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 ?
The center ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 is (2,3)