What is the center ((y-3)^2)/(49)-((x+2)^2)/(16)=1 ?

The center ((y-3)^2)/(49)-((x+2)^2)/(16)=1 is (-2,3)

Popular >

center ((y-3)^2)/(49)-((x+2)^2)/(16)=1

center

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

(- 2, 3)

Solution steps

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{7 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 3), a = 7, b = 4

And the center is:

(- 2, 3)

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{16} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

What is the center ((y-3)^2)/(49)-((x+2)^2)/(16)=1 ?
The center ((y-3)^2)/(49)-((x+2)^2)/(16)=1 is (-2,3)