What is the center (y^2)/(25)-x^2=1 ?

The center (y^2)/(25)-x^2=1 is (0,0)

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center (y^2)/(25)-x^2=1

center

\frac{y ^{2}}{25} - x^{2} = 1

(0, 0)

Solution steps

\frac{y ^{2}}{25} - x^{2} = 1

Rewrite

\frac{y ^{2}}{25} - x^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 1

And the center is:

(0, 0)

- 4 x^{2} + y^{2} + 8 y - 20 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

4 x^{2} + 8 x - 4 y^{2} + 12 y - 3 = 0

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

+ 0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400