What is the eccentricity (x^2}{36}-\frac{y^2)/4 =1 ?

The eccentricity (x^2}{36}-\frac{y^2)/4 =1 is (sqrt(10))/3

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eccentricity (x^2}{36}-\frac{y^2)/4 =1

eccentricity

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

\frac{10}{3}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

= \frac{6 ^{2} + 2 ^{2}}{6}

Refine

= \frac{10}{3}

\frac{x ^{2}}{40} - \frac{y ^{2}}{120} = 1

0 = - \frac{400}{9} x^{2} + 16 y^{2} + 400

\frac{x ^{2}}{121} - \frac{y ^{2}}{81} = 1

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

x^{2} - \frac{y ^{2}}{4} = 1

What is the eccentricity (x^2}{36}-\frac{y^2)/4 =1 ?
The eccentricity (x^2}{36}-\frac{y^2)/4 =1 is (sqrt(10))/3