What is the eccentricity x^2-(y^2)/4 =1 ?

The eccentricity x^2-(y^2)/4 =1 is square root of 5

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eccentricity x^2-(y^2)/4 =1

eccentricity

x^{2} - \frac{y ^{2}}{4} = 1

5

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

x^{2} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

= \frac{1 ^{2} + 2 ^{2}}{1}

Refine

= 5

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

What is the eccentricity x^2-(y^2)/4 =1 ?
The eccentricity x^2-(y^2)/4 =1 is square root of 5