What is the eccentricity (x^2)/(27)-(y^2)/(216)=1 ?

The eccentricity (x^2)/(27)-(y^2)/(216)=1 is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

eccentricity (x^2)/(27)-(y^2)/(216)=1

eccentricity

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1

3

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{27} - \frac{y ^{2}}{216} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 33, b = 66

= \frac{( 3 3 ) ^{2} + ( 6 6 ) ^{2}}{3 3}

Refine

= 3

x^{2} - \frac{y ^{2}}{4} = 1

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

What is the eccentricity (x^2)/(27)-(y^2)/(216)=1 ?
The eccentricity (x^2)/(27)-(y^2)/(216)=1 is 3