What is x^2+y^2-2x+4y-31=0 ?

The solution to x^2+y^2-2x+4y-31=0 is Circle with (a,b)=(1,-2),r=6

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x^2+y^2-2x+4y-31=0

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

(a, b) = (1, - 2), r = 6

Solution steps

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

Rewrite

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 6

(x + 4)^{2} = 12 y - 24

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

y^{2} = 16 x

(x - 3)^{2} + (y + 5)^{2} = 16

y^{2} - 8 x - 16 = 0

What is x^2+y^2-2x+4y-31=0 ?
The solution to x^2+y^2-2x+4y-31=0 is Circle with (a,b)=(1,-2),r=6