What is 4y^2-48x-20y=71 ?

The solution to 4y^2-48x-20y=71 is Parabola with (h,k)=(-2, 5/2),p=3

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4y^2-48x-20y=71

4 y^{2} - 48 x - 20 y = 71

(h, k) = (- 2, \frac{5}{2}), p = 3

Solution steps

4 y^{2} - 48 x - 20 y = 71

Rewrite

4 y^{2} - 48 x - 20 y = 71

in the standard form

4 \cdot 3 (x - (- 2)) = (y - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{5}{2}), p = 3

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

f (x) = x^{2} - 6 x + 8

x^{2} - y^{2} = 10 (x - y) + 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

F = \frac{m v ^{2}}{r}

What is 4y^2-48x-20y=71 ?
The solution to 4y^2-48x-20y=71 is Parabola with (h,k)=(-2, 5/2),p=3