What is the foci (y^2}{25}-\frac{x^2)/4 =1 ?

The foci (y^2}{25}-\frac{x^2)/4 =1 is (0,sqrt(29)),(0,-sqrt(29))

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foci (y^2}{25}-\frac{x^2)/4 =1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

(0, 29), (0, - 29)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 2^{2} : 29

(0, 0 + 29), (0, 0 - 29)

Refine

(0, 29), (0, - 29)

f (x) = x^{2} - 6 x + 8

x^{2} - y^{2} = 10 (x - y) + 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

F = \frac{m v ^{2}}{r}

(x - 0)^{2} + (y - 20)^{2} = 400

What is the foci (y^2}{25}-\frac{x^2)/4 =1 ?
The foci (y^2}{25}-\frac{x^2)/4 =1 is (0,sqrt(29)),(0,-sqrt(29))