What is (x+92)^2+(y+54)^2=73 ?

The solution to (x+92)^2+(y+54)^2=73 is Circle with (a,b)=(-92,-54),r=sqrt(73)

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(x+92)^2+(y+54)^2=73

(x + 92)^{2} + (y + 54)^{2} = 73

(a, b) = (- 92, - 54), r = 73

Solution steps

(x + 92)^{2} + (y + 54)^{2} = 73

Rewrite

(x + 92)^{2} + (y + 54)^{2} = 73

in the form of the standard circle equation

(x - (- 92))^{2} + (y - (- 54))^{2} = (73)^{2}

Therefore the circle properties are:

(a, b) = (- 92, - 54), r = 73

x^{2} - 4 x + y^{2} - 2 y = - 2

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

\frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

y^{2} = 1 - x

What is (x+92)^2+(y+54)^2=73 ?
The solution to (x+92)^2+(y+54)^2=73 is Circle with (a,b)=(-92,-54),r=sqrt(73)