What is x^2+y^2-2x=0 ?

The solution to x^2+y^2-2x=0 is Circle with (a,b)=(1,0),r=1

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x^2+y^2-2x=0

x^{2} + y^{2} - 2 x = 0

(a, b) = (1, 0), r = 1

Solution steps

x^{2} + y^{2} - 2 x = 0

Rewrite

x^{2} + y^{2} - 2 x = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 1

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

y^{2} + 4 y + 8 x - 12 = 0

13 x^{2} + 49 y^{2} = 637

4 x^{2} + 9 y^{2} = 36

x^{2} + \frac{y ^{2}}{16} = 1

What is x^2+y^2-2x=0 ?
The solution to x^2+y^2-2x=0 is Circle with (a,b)=(1,0),r=1