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Popular >

foci y^2=32x

Solution

foci

y^{2} = 32 x

Solution

(8, 0)

Solution steps

Rewrite

y^{2} = 32 x

in the standard form:

4 \cdot 8 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 8

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 8, 0)

Refine

(8, 0)

Popular Examples

foci 16x^2-9y^2=144 foci

16 x^{2} - 9 y^{2} = 144

vertices 3x^2+y^2+18x-2y-8=0 vertices

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

directrix x^2=12y directrix

x^{2} = 12 y

x^2+y^2-6x+4y+4=0

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

directrix y= 1/2 x^2 directrix

y = \frac{1}{2} x^{2}

Frequently Asked Questions (FAQ)

What is the foci y^2=32x ?
The foci y^2=32x is (8,0)