What is the vertices 3x^2+y^2+18x-2y-8=0 ?

The vertices 3x^2+y^2+18x-2y-8=0 is (-3,7),(-3,-5)

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vertices 3x^2+y^2+18x-2y-8=0

vertices

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

(- 3, 7), (- 3, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0 :

Ellipse with center

(h, k) = (- 3, 1), b = 6, a = 23

(- 3, 1 + 6), (- 3, 1 - 6)

Refine

(- 3, 7), (- 3, - 5)

x^{2} = 12 y

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

y = \frac{1}{2} x^{2}

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

x^{2} = 3 y

What is the vertices 3x^2+y^2+18x-2y-8=0 ?
The vertices 3x^2+y^2+18x-2y-8=0 is (-3,7),(-3,-5)