What is the derivative of x^2e^x ?

The derivative of x^2e^x is 2xe^x+e^xx^2

What is the first derivative of x^2e^x ?

The first derivative of x^2e^x is 2xe^x+e^xx^2

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derivative of

x^{2} e^{x}

2 x e^{x} + e^{x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = e^{x}

= \frac{d}{d x} (x^{2}) e^{x} + \frac{d}{d x} (e^{x}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} x^{2}

e^{- 2 x}

f (x) = 2 x^{3} + 4 x

(- 1, 7), (3, - 3)

f (x) = 8 x^{2} + 11 x, at x = 7

3 x - 4 y = 7

What is the derivative of x^2e^x ?
The derivative of x^2e^x is 2xe^x+e^xx^2
What is the first derivative of x^2e^x ?
The first derivative of x^2e^x is 2xe^x+e^xx^2