What are the solutions to the equation x^2+16x+64=-81 ?

The solutions to the equation x^2+16x+64=-81 are x=-8+9i,x=-8-9i

Find the zeros of x^2+16x+64=-81

The zeros of x^2+16x+64=-81 are x=-8+9i,x=-8-9i

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x^{2} + 16 x + 64 = - 81

x = - 8 + 9 i, x = - 8 - 9 i

Solution steps

x^{2} + 16 x + 64 = - 81

Move

81

to the left side

x^{2} + 16 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 145}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 145 : 18 i

x_{1, 2} = \frac{- 16 \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 18 i}{2 \cdot 1}, x_{2} = \frac{- 16 - 18 i}{2 \cdot 1}

x = \frac{- 16 + 18 i}{2 \cdot 1} : - 8 + 9 i

x = \frac{- 16 - 18 i}{2 \cdot 1} : - 8 - 9 i

The solutions to the quadratic equation are:

x = - 8 + 9 i, x = - 8 - 9 i

x^{2} - 12 x - 64 = 0

2 w^{2} - 3 w - 14 = 0

3 b^{2} + 6 b + 91 = 0

x^{2} - 12 x = - 11

lo g_{1} (2) = 3

What are the solutions to the equation x^2+16x+64=-81 ?
The solutions to the equation x^2+16x+64=-81 are x=-8+9i,x=-8-9i
Find the zeros of x^2+16x+64=-81
The zeros of x^2+16x+64=-81 are x=-8+9i,x=-8-9i