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Popular >

y^'=20x-2

Solution

y^{^{'}} = 20 x - 2

Solution

y = 10 x^{2} - 2 x + c_{1}

Solution steps

y^{'} (x) = 20 x - 2

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 20 x - 2 d x

\int 20 x - 2 d x = 10 x^{2} - 2 x + c_{1}

y = 10 x^{2} - 2 x + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=20x-2 ?
The solution for y^'=20x-2 is y=10x^2-2x+c_{1}