What is the derivative of sqrt(2)x+e^x+e^{-x} ?

The derivative of sqrt(2)x+e^x+e^{-x} is sqrt(2)+e^x-e^{-x}

What is the first derivative of sqrt(2)x+e^x+e^{-x} ?

The first derivative of sqrt(2)x+e^x+e^{-x} is sqrt(2)+e^x-e^{-x}

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\frac{d}{d x} (2 x + e^{x} + e^{- x})

2 + e^{x} - e^{- x}

Solution steps

\frac{d}{d x} (2 x + e^{x} + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{- x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 2 + e^{x} - e^{- x}

F (x) = sin (7 x) + cos (4 x)

\frac{d}{d x} (\frac{10 x}{x ^{2} + 1})

(3 x + 8)^{2}

\int cos (7 t) d t

2 x^{3} - 1

What is the derivative of sqrt(2)x+e^x+e^{-x} ?
The derivative of sqrt(2)x+e^x+e^{-x} is sqrt(2)+e^x-e^{-x}
What is the first derivative of sqrt(2)x+e^x+e^{-x} ?
The first derivative of sqrt(2)x+e^x+e^{-x} is sqrt(2)+e^x-e^{-x}