What is the radius x^2+y^2+10x-6y+18=0 ?

The radius x^2+y^2+10x-6y+18=0 is r=4

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radius x^2+y^2+10x-6y+18=0

radius

x^{2} + y^{2} + 10 x - 6 y + 18 = 0

r = 4

Solution steps

x^{2} + y^{2} + 10 x - 6 y + 18 = 0

Rewrite

x^{2} + y^{2} + 10 x - 6 y + 18 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 5, 3), r = 4

And the radius is:

r = 4

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

(x + 1)^{2} + (y - 2)^{2} = 9

x^{2} + (y - 1)^{2} = 1

x^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} - 2 y - 8 = 0