What is the radius (x+1)^2+(y-1)^2=40 ?

The radius (x+1)^2+(y-1)^2=40 is r=sqrt(40)

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radius (x+1)^2+(y-1)^2=40

radius

(x + 1)^{2} + (y - 1)^{2} = 40

r = 40

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 40

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 40

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (40)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 40

And the radius is:

r = 40

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5)

x^{2} + y^{2} + 10 x + 8 y - 4 = 0

(x - 3)^{2} + (y - 5)^{2} = 24

x^{2} + y^{2} + 4 x - 6 y - 12 = 0

x^{2} - 8 x + y^{2} + 6 y = - 9

What is the radius (x+1)^2+(y-1)^2=40 ?
The radius (x+1)^2+(y-1)^2=40 is r=sqrt(40)