What is the foci 9x^2-18x-16y^2-64y=199 ?

The foci 9x^2-18x-16y^2-64y=199 is (6,-2),(-4,-2)

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foci 9x^2-18x-16y^2-64y=199

foci

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

(6, - 2), (- 4, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199 :

Right-left Hyperbola with

(h, k) = (1, - 2), a = 4, b = 3

(1 + c, - 2), (1 - c, - 2)

Compute

c :

c = 4^{2} + 3^{2} : 5

(1 + 5, - 2), (1 - 5, - 2)

Refine

(6, - 2), (- 4, - 2)

18 x^{2} - 32 y^{2} = 2

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

- 9 x^{2} + y^{2} + 54 x - 117 = 0

What is the foci 9x^2-18x-16y^2-64y=199 ?
The foci 9x^2-18x-16y^2-64y=199 is (6,-2),(-4,-2)