y^2+2y+x=0

Solution

y^{2} + 2 y + x = 0

(h, k) = (1, - 1), p = - \frac{1}{4}

Solution steps

y^{2} + 2 y + x = 0

Rewrite

y^{2} + 2 y + x = 0

in the standard form

4 (- \frac{1}{4}) (x - 1) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (1, - 1), p = - \frac{1}{4}

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

x^{2} + 2 y - 6 = 0

4 y^{2} - 48 x - 20 y = 71

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

What is y^2+2y+x=0 ?
The solution to y^2+2y+x=0 is Parabola with (h,k)=(1,-1),p=-1/4