x^2+2y-6=0

Solution

x^{2} + 2 y - 6 = 0

(h, k) = (0, 3), p = - \frac{1}{2}

Solution steps

x^{2} + 2 y - 6 = 0

Rewrite

x^{2} + 2 y - 6 = 0

in the standard form:

4 (- \frac{1}{2}) (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = - \frac{1}{2}

4 y^{2} - 48 x - 20 y = 71

\frac{y ^{2}}{25} - \frac{x ^{2}}{4} = 1

f (x) = x^{2} - 6 x + 8

x^{2} - y^{2} = 10 (x - y) + 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

What is x^2+2y-6=0 ?
The solution to x^2+2y-6=0 is Parabola with (h,k)=(0,3),p=-1/2