What is (x-5)^2+(y-9)^2=4 ?

The solution to (x-5)^2+(y-9)^2=4 is Circle with (a,b)=(5,9),r=2

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(x-5)^2+(y-9)^2=4

(x - 5)^{2} + (y - 9)^{2} = 4

(a, b) = (5, 9), r = 2

Solution steps

(x - 5)^{2} + (y - 9)^{2} = 4

Rewrite

(x - 5)^{2} + (y - 9)^{2} = 4

in the form of the standard circle equation

(x - 5)^{2} + (y - 9)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, 9), r = 2

y^{2} = - 14 x

x^{2} + y^{2} - 2 x = 0

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

y^{2} + 4 y + 8 x - 12 = 0

13 x^{2} + 49 y^{2} = 637

What is (x-5)^2+(y-9)^2=4 ?
The solution to (x-5)^2+(y-9)^2=4 is Circle with (a,b)=(5,9),r=2