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Popular >

foci y^2=-14x

Solution

foci

y^{2} = - 14 x

Solution

(- \frac{7}{2}, 0)

Solution steps

Rewrite

y^{2} = - 14 x

in the standard form:

4 (- \frac{7}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{7}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{7}{2}), 0)

Refine

(- \frac{7}{2}, 0)

Popular Examples

x^{2} + y^{2} - 2 x = 0

center x^2+y^2-18x-14y+124=0 center

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

y^{2} + 4 y + 8 x - 12 = 0

eccentricity 13x^2+49y^2=637 eccentricity

13 x^{2} + 49 y^{2} = 637

vertices 4x^2+9y^2=36 vertices

4 x^{2} + 9 y^{2} = 36

Frequently Asked Questions (FAQ)

What is the foci y^2=-14x ?
The foci y^2=-14x is (-7/2 ,0)