What is the radius x^2+(y-1)^2=16 ?

The radius x^2+(y-1)^2=16 is r=4

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radius x^2+(y-1)^2=16

radius

x^{2} + (y - 1)^{2} = 16

r = 4

Solution steps

x^{2} + (y - 1)^{2} = 16

Rewrite

x^{2} + (y - 1)^{2} = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 10 x - 6 y + 18 = 0

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

(x + 1)^{2} + (y - 2)^{2} = 9

x^{2} + (y - 1)^{2} = 1

x^{2} + (y - 5)^{2} = 25