What is x^2-10x+y^2+6y-1=0 ?

The solution to x^2-10x+y^2+6y-1=0 is Circle with (a,b)=(5,-3),r=sqrt(35)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-10x+y^2+6y-1=0

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

(a, b) = (5, - 3), r = 35

Solution steps

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

Rewrite

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 35

x = - 8 y^{2}

(x - 5)^{2} + (y - 9)^{2} = 4

y^{2} = - 14 x

x^{2} + y^{2} - 2 x = 0

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

What is x^2-10x+y^2+6y-1=0 ?
The solution to x^2-10x+y^2+6y-1=0 is Circle with (a,b)=(5,-3),r=sqrt(35)